Sorry, I forgot to answer your last question. It turns out that, because of how the algorithm works, the number of blocks shouldn't matter. Since it is discretizing time windows in 10ms increments, the granularity of the "effective blocks" is small enough that putting two separate large blocks on the screen, each for a shorter period of time, is roughly equivalent to putting a single large block on the screen for twice as long (for synchronization purposes, that is).